3x^2+6x=58

Solution for 3x^2+6x=58 equation:

3x^2+6x=58

We move all terms to the left:

3x^2+6x-(58)=0

a = 3; b = 6; c = -58;
Δ = b2-4ac
Δ = 62-4·3·(-58)
Δ = 732
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{732}=\sqrt{4*183}=\sqrt{4}*\sqrt{183}=2\sqrt{183}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{183}}{2*3}=\frac{-6-2\sqrt{183}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{183}}{2*3}=\frac{-6+2\sqrt{183}}{6}
$